Base | Representation |
---|---|
bin | 101101010011011001010… |
… | …111000110001110101001 |
3 | 102000121201110202012002002 |
4 | 231103121113012032221 |
5 | 402001314434024001 |
6 | 10342104041220345 |
7 | 440631034106135 |
oct | 55233127061651 |
9 | 12017643665062 |
10 | 3113203033001 |
11 | aa0335a509a6 |
12 | 4234394916b5 |
13 | 19775c7bacb9 |
14 | aa9736543c5 |
15 | 55eacb3846b |
hex | 2d4d95c63a9 |
3113203033001 has 2 divisors, whose sum is σ = 3113203033002. Its totient is φ = 3113203033000.
The previous prime is 3113203032997. The next prime is 3113203033027. The reversal of 3113203033001 is 1003303023113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1971564207376 + 1141638825625 = 1404124^2 + 1068475^2 .
It is a cyclic number.
It is not a de Polignac number, because 3113203033001 - 22 = 3113203032997 is a prime.
It is not a weakly prime, because it can be changed into another prime (3113203033051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556601516500 + 1556601516501.
It is an arithmetic number, because the mean of its divisors is an integer number (1556601516501).
Almost surely, 23113203033001 is an apocalyptic number.
It is an amenable number.
3113203033001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113203033001 is an equidigital number, since it uses as much as digits as its factorization.
3113203033001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 20.
Adding to 3113203033001 its reverse (1003303023113), we get a palindrome (4116506056114).
The spelling of 3113203033001 in words is "three trillion, one hundred thirteen billion, two hundred three million, thirty-three thousand, one".
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