Base | Representation |
---|---|
bin | 1110001010000100000111… |
… | …00111011010010001111011 |
3 | 11002020012110202002221010112 |
4 | 13011002003213122101323 |
5 | 13040032101030423323 |
6 | 150113523101534535 |
7 | 6362136142131314 |
oct | 705020347322173 |
9 | 132205422087115 |
10 | 31132131107963 |
11 | 9a13076441026 |
12 | 35a974787444b |
13 | 144a993c6c832 |
14 | 798b35d2560b |
15 | 38ec41513178 |
hex | 1c50839da47b |
31132131107963 has 2 divisors, whose sum is σ = 31132131107964. Its totient is φ = 31132131107962.
The previous prime is 31132131107927. The next prime is 31132131107983. The reversal of 31132131107963 is 36970113123113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31132131107963 - 26 = 31132131107899 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31132131107963.
It is not a weakly prime, because it can be changed into another prime (31132131107983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15566065553981 + 15566065553982.
It is an arithmetic number, because the mean of its divisors is an integer number (15566065553982).
Almost surely, 231132131107963 is an apocalyptic number.
31132131107963 is a deficient number, since it is larger than the sum of its proper divisors (1).
31132131107963 is an equidigital number, since it uses as much as digits as its factorization.
31132131107963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 41.
The spelling of 31132131107963 in words is "thirty-one trillion, one hundred thirty-two billion, one hundred thirty-one million, one hundred seven thousand, nine hundred sixty-three".
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