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311321434321 is a prime number
BaseRepresentation
bin1001000011111000011…
…01000001100011010001
31002202120112012110222101
410201330031001203101
520100041241344241
6355004042440401
731330556346442
oct4417415014321
91082515173871
10311321434321
11110037919497
1250404b03101
132348551a281
14110d49a52c9
158171592e31
hex487c3418d1

311321434321 has 2 divisors, whose sum is σ = 311321434322. Its totient is φ = 311321434320.

The previous prime is 311321434297. The next prime is 311321434327. The reversal of 311321434321 is 123434123113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 307758657600 + 3562776721 = 554760^2 + 59689^2 .

It is a cyclic number.

It is not a de Polignac number, because 311321434321 - 29 = 311321433809 is a prime.

It is a super-3 number, since 3×3113214343213 (a number of 35 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 311321434321.

It is not a weakly prime, because it can be changed into another prime (311321434327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155660717160 + 155660717161.

It is an arithmetic number, because the mean of its divisors is an integer number (155660717161).

Almost surely, 2311321434321 is an apocalyptic number.

It is an amenable number.

311321434321 is a deficient number, since it is larger than the sum of its proper divisors (1).

311321434321 is an equidigital number, since it uses as much as digits as its factorization.

311321434321 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5184, while the sum is 28.

Adding to 311321434321 its reverse (123434123113), we get a palindrome (434755557434).

The spelling of 311321434321 in words is "three hundred eleven billion, three hundred twenty-one million, four hundred thirty-four thousand, three hundred twenty-one".