Base | Representation |
---|---|
bin | 101101010011011010111… |
… | …111101110110111111001 |
3 | 102000121210101100202012212 |
4 | 231103122333232313321 |
5 | 402001343444244312 |
6 | 10342110501144505 |
7 | 440631516210323 |
oct | 55233277566771 |
9 | 12017711322185 |
10 | 3113230462457 |
11 | aa034a486075 |
12 | 4234466bb135 |
13 | 1977653a2c4b |
14 | aa977154613 |
15 | 55eb0255822 |
hex | 2d4dafeedf9 |
3113230462457 has 2 divisors, whose sum is σ = 3113230462458. Its totient is φ = 3113230462456.
The previous prime is 3113230462399. The next prime is 3113230462471. The reversal of 3113230462457 is 7542640323113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3100472985856 + 12757476601 = 1760816^2 + 112949^2 .
It is a cyclic number.
It is not a de Polignac number, because 3113230462457 - 238 = 2838352555513 is a prime.
It is not a weakly prime, because it can be changed into another prime (3113230462157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556615231228 + 1556615231229.
It is an arithmetic number, because the mean of its divisors is an integer number (1556615231229).
Almost surely, 23113230462457 is an apocalyptic number.
It is an amenable number.
3113230462457 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113230462457 is an equidigital number, since it uses as much as digits as its factorization.
3113230462457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 41.
The spelling of 3113230462457 in words is "three trillion, one hundred thirteen billion, two hundred thirty million, four hundred sixty-two thousand, four hundred fifty-seven".
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