Base | Representation |
---|---|
bin | 101101010011011011000… |
… | …101100110110001001011 |
3 | 102000121210111020222020112 |
4 | 231103123011212301023 |
5 | 402001344343031443 |
6 | 10342110554144535 |
7 | 440631535252205 |
oct | 55233305466113 |
9 | 12017714228215 |
10 | 3113232002123 |
11 | aa0350337921 |
12 | 42344712214b |
13 | 1977657c19a9 |
14 | aa977435775 |
15 | 55eb045bb18 |
hex | 2d4db166c4b |
3113232002123 has 2 divisors, whose sum is σ = 3113232002124. Its totient is φ = 3113232002122.
The previous prime is 3113232002113. The next prime is 3113232002141. The reversal of 3113232002123 is 3212002323113.
3113232002123 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3113232002123 - 226 = 3113164893259 is a prime.
It is not a weakly prime, because it can be changed into another prime (3113232002113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556616001061 + 1556616001062.
It is an arithmetic number, because the mean of its divisors is an integer number (1556616001062).
Almost surely, 23113232002123 is an apocalyptic number.
3113232002123 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113232002123 is an equidigital number, since it uses as much as digits as its factorization.
3113232002123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 3113232002123 its reverse (3212002323113), we get a palindrome (6325234325236).
The spelling of 3113232002123 in words is "three trillion, one hundred thirteen billion, two hundred thirty-two million, two thousand, one hundred twenty-three".
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