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311323210211249 is a prime number
BaseRepresentation
bin100011011001001011001010…
…1010110101101111110110001
31111211022012121210122012010022
41012302112111112231332301
5311301204413303224444
63022043524112213225
7122401234241302325
oct10662262526557661
91454265553565108
10311323210211249
1190219482a919a5
122ab0063523a215
1310493864137982
1456c41a38bb985
1525ed3701ab9ee
hex11b25955adfb1

311323210211249 has 2 divisors, whose sum is σ = 311323210211250. Its totient is φ = 311323210211248.

The previous prime is 311323210211177. The next prime is 311323210211317. The reversal of 311323210211249 is 942112012323113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 268016189440000 + 43307020771249 = 16371200^2 + 6580807^2 .

It is a cyclic number.

It is not a de Polignac number, because 311323210211249 - 236 = 311254490734513 is a prime.

It is a super-2 number, since 2×3113232102112492 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (311323210211149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155661605105624 + 155661605105625.

It is an arithmetic number, because the mean of its divisors is an integer number (155661605105625).

Almost surely, 2311323210211249 is an apocalyptic number.

It is an amenable number.

311323210211249 is a deficient number, since it is larger than the sum of its proper divisors (1).

311323210211249 is an equidigital number, since it uses as much as digits as its factorization.

311323210211249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 311323210211249 in words is "three hundred eleven trillion, three hundred twenty-three billion, two hundred ten million, two hundred eleven thousand, two hundred forty-nine".