Base | Representation |
---|---|
bin | 100011011001001110011010… |
… | …1111110101001011001101111 |
3 | 1111211022212122221011020212021 |
4 | 1012302130311332221121233 |
5 | 311301313222200000421 |
6 | 3022051041443451011 |
7 | 122401602404442445 |
oct | 10662346576513157 |
9 | 1454285587136767 |
10 | 311330200000111 |
11 | 9022143a5a1806 |
12 | 2ab01a66086a67 |
13 | 104944092a6c06 |
14 | 56c4667d3ab95 |
15 | 25ed62db5a341 |
hex | 11b2735fa966f |
311330200000111 has 16 divisors (see below), whose sum is σ = 319627235450880. Its totient is φ = 303102955349920.
The previous prime is 311330200000103. The next prime is 311330200000123. The reversal of 311330200000111 is 111000002033113.
It is a cyclic number.
It is not a de Polignac number, because 311330200000111 - 23 = 311330200000103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311330200000151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 361136100 + ... + 361997158.
It is an arithmetic number, because the mean of its divisors is an integer number (19976702215680).
Almost surely, 2311330200000111 is an apocalyptic number.
311330200000111 is a deficient number, since it is larger than the sum of its proper divisors (8297035450769).
311330200000111 is a wasteful number, since it uses less digits than its factorization.
311330200000111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 901574.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 311330200000111 its reverse (111000002033113), we get a palindrome (422330202033224).
The spelling of 311330200000111 in words is "three hundred eleven trillion, three hundred thirty billion, two hundred million, one hundred eleven", and thus it is an aban number.
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