31133111111040 has 256 divisors, whose sum is σ = 107637041211840. Its totient is φ = 7623219609600.

The previous prime is 31133111111027. The next prime is 31133111111051. The reversal of 31133111111040 is 4011111133113.

It is a junction number, because it is equal to n+sod(n) for n = 31133111110998 and 31133111111016.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10293871 + ... + 12970350.

Almost surely, 2^{31133111111040} is an apocalyptic number.

31133111111040 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

31133111111040 is an abundant number, since it is smaller than the sum of its proper divisors (76503930100800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31133111111040 is a wasteful number, since it uses less digits than its factorization.

31133111111040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23264301 (or 23264289 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 21.

Adding to 31133111111040 its reverse (4011111133113), we get a palindrome (35144222244153).

The spelling of 31133111111040 in words is "thirty-one trillion, one hundred thirty-three billion, one hundred eleven million, one hundred eleven thousand, forty".