Base | Representation |
---|---|
bin | 1011100110010001… |
… | …0110011101001001 |
3 | 22000222020202002102 |
4 | 2321210112131021 |
5 | 22334002022441 |
6 | 1232533043145 |
7 | 140102506361 |
oct | 27144263511 |
9 | 8028222072 |
10 | 3113314121 |
11 | 1358425a85 |
12 | 72a7864b5 |
13 | 3a800a208 |
14 | 2176a19a1 |
15 | 1334c869b |
hex | b9916749 |
3113314121 has 2 divisors, whose sum is σ = 3113314122. Its totient is φ = 3113314120.
The previous prime is 3113314117. The next prime is 3113314133. The reversal of 3113314121 is 1214133113.
3113314121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2209470025 + 903844096 = 47005^2 + 30064^2 .
It is an emirp because it is prime and its reverse (1214133113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3113314121 - 22 = 3113314117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3113314093 and 3113314102.
It is not a weakly prime, because it can be changed into another prime (3113314151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556657060 + 1556657061.
It is an arithmetic number, because the mean of its divisors is an integer number (1556657061).
Almost surely, 23113314121 is an apocalyptic number.
It is an amenable number.
3113314121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113314121 is an equidigital number, since it uses as much as digits as its factorization.
3113314121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 216, while the sum is 20.
The square root of 3113314121 is about 55797.0798608673. The cubic root of 3113314121 is about 1460.1842078516.
Adding to 3113314121 its reverse (1214133113), we get a palindrome (4327447234).
It can be divided in two parts, 31133 and 14121, that added together give a palindrome (45254).
The spelling of 3113314121 in words is "three billion, one hundred thirteen million, three hundred fourteen thousand, one hundred twenty-one".
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