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31133144034 = 2322375200831
BaseRepresentation
bin11100111111101011…
…100001001111100010
32222100201111120202200
4130333223201033202
51002230041102114
622145151154030
72151336233526
oct347753411742
988321446680
1031133144034
1112226936a03
12604a515916
132c2207bb25
141714b33d86
15c2335a409
hex73fae13e2

31133144034 has 24 divisors (see below), whose sum is σ = 70387978752. Its totient is φ = 9926509560.

The previous prime is 31133144027. The next prime is 31133144083. The reversal of 31133144034 is 43044133113.

31133144034 is a `hidden beast` number, since 311 + 3 + 314 + 4 + 0 + 34 = 666.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 31133143989 and 31133144007.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 37600002 + ... + 37600829.

It is an arithmetic number, because the mean of its divisors is an integer number (2932832448).

Almost surely, 231133144034 is an apocalyptic number.

31133144034 is an abundant number, since it is smaller than the sum of its proper divisors (39254834718).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31133144034 is a wasteful number, since it uses less digits than its factorization.

31133144034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75200862 (or 75200859 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 31133144034 its reverse (43044133113), we get a palindrome (74177277147).

The spelling of 31133144034 in words is "thirty-one billion, one hundred thirty-three million, one hundred forty-four thousand, thirty-four".

Divisors: 1 2 3 6 9 18 23 46 69 138 207 414 75200831 150401662 225602493 451204986 676807479 1353614958 1729619113 3459238226 5188857339 10377714678 15566572017 31133144034