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311340400100242 = 2155670200050121
BaseRepresentation
bin100011011001010011001010…
…1111100111100001110010010
31111211100211222210110000202121
41012302212111330330032102
5311302000114411201432
63022055445535204454
7122402413232036632
oct10662462574741622
91454324883400677
10311340400100242
11902257a4257a27
122ab03a3207672a
1310495373585116
1456c4d548aa6c2
1525eda29392197
hex11b2995f3c392

311340400100242 has 4 divisors (see below), whose sum is σ = 467010600150366. Its totient is φ = 155670200050120.

The previous prime is 311340400100231. The next prime is 311340400100267. The reversal of 311340400100242 is 242001004043113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 205456073720121 + 105884326380121 = 14333739^2 + 10290011^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77835100025059 + ... + 77835100025062.

Almost surely, 2311340400100242 is an apocalyptic number.

311340400100242 is a deficient number, since it is larger than the sum of its proper divisors (155670200050124).

311340400100242 is a wasteful number, since it uses less digits than its factorization.

311340400100242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 155670200050123.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 311340400100242 its reverse (242001004043113), we get a palindrome (553341404143355).

The spelling of 311340400100242 in words is "three hundred eleven trillion, three hundred forty billion, four hundred million, one hundred thousand, two hundred forty-two".

Divisors: 1 2 155670200050121 311340400100242