3113413102042 has 4 divisors (see below), whose sum is σ = 4670119653066. Its totient is φ = 1556706551020.

The previous prime is 3113413102027. The next prime is 3113413102091. The reversal of 3113413102042 is 2402013143113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3015463507081 + 97949594961 = 1736509^2 + 312969^2 .

It is a super-2 number, since 2×3113413102042² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3113413101998 and 3113413102016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 778353275509 + ... + 778353275512.

Almost surely, 2^{3113413102042} is an apocalyptic number.

3113413102042 is a deficient number, since it is larger than the sum of its proper divisors (1556706551024).

3113413102042 is a wasteful number, since it uses less digits than its factorization.

3113413102042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1556706551023.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 3113413102042 its reverse (2402013143113), we get a palindrome (5515426245155).

The spelling of 3113413102042 in words is "three trillion, one hundred thirteen billion, four hundred thirteen million, one hundred two thousand, forty-two".