Base | Representation |
---|---|
bin | 100011011001010011101010… |
… | …0001100010010110000110001 |
3 | 1111211100221200120022111011100 |
4 | 1012302213110030102300301 |
5 | 311302004234220441423 |
6 | 3022100141320235013 |
7 | 122402451141510255 |
oct | 10662472414226061 |
9 | 1454327616274140 |
10 | 311341444312113 |
11 | 9022618a728846 |
12 | 2ab0408390ba69 |
13 | 104954aba01c77 |
14 | 56c5013446265 |
15 | 25eda8ada8343 |
hex | 11b29d4312c31 |
311341444312113 has 24 divisors (see below), whose sum is σ = 461555989970400. Its totient is φ = 202165700514624.
The previous prime is 311341444312103. The next prime is 311341444312121. The reversal of 311341444312113 is 311213444143113.
311341444312113 is a `hidden beast` number, since 3 + 1 + 1 + 3 + 4 + 1 + 4 + 4 + 431 + 211 + 3 = 666.
It is not a de Polignac number, because 311341444312113 - 210 = 311341444311089 is a prime.
It is not an unprimeable number, because it can be changed into a prime (311341444312103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2900625003 + ... + 2900732336.
It is an arithmetic number, because the mean of its divisors is an integer number (19231499582100).
Almost surely, 2311341444312113 is an apocalyptic number.
It is an amenable number.
311341444312113 is a deficient number, since it is larger than the sum of its proper divisors (150214545658287).
311341444312113 is a wasteful number, since it uses less digits than its factorization.
311341444312113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5801357501 (or 5801357498 counting only the distinct ones).
The product of its digits is 41472, while the sum is 36.
Adding to 311341444312113 its reverse (311213444143113), we get a palindrome (622554888455226).
The spelling of 311341444312113 in words is "three hundred eleven trillion, three hundred forty-one billion, four hundred forty-four million, three hundred twelve thousand, one hundred thirteen".
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