Base | Representation |
---|---|
bin | 1011100110010011… |
… | …0011001111110111 |
3 | 22000222110201212100 |
4 | 2321210303033313 |
5 | 22334014311210 |
6 | 1232535353143 |
7 | 140103510246 |
oct | 27144631767 |
9 | 8028421770 |
10 | 3113432055 |
11 | 13584a6648 |
12 | 72a8227b3 |
13 | 3a804bab6 |
14 | 2176d295d |
15 | 1334ed5c0 |
hex | b99333f7 |
3113432055 has 24 divisors (see below), whose sum is σ = 5680649520. Its totient is φ = 1573102080.
The previous prime is 3113432039. The next prime is 3113432089. The reversal of 3113432055 is 5502343113.
3113432055 is a `hidden beast` number, since 311 + 343 + 2 + 0 + 5 + 5 = 666.
It is not a de Polignac number, because 3113432055 - 24 = 3113432039 is a prime.
It is a super-2 number, since 2×31134320552 = 19386918322203046050, which contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1819866 + ... + 1821575.
It is an arithmetic number, because the mean of its divisors is an integer number (236693730).
Almost surely, 23113432055 is an apocalyptic number.
3113432055 is a deficient number, since it is larger than the sum of its proper divisors (2567217465).
3113432055 is a wasteful number, since it uses less digits than its factorization.
3113432055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3641471 (or 3641468 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
The square root of 3113432055 is about 55798.1366624370. The cubic root of 3113432055 is about 1460.2026451377.
Adding to 3113432055 its reverse (5502343113), we get a palindrome (8615775168).
The spelling of 3113432055 in words is "three billion, one hundred thirteen million, four hundred thirty-two thousand, fifty-five".
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