3113504113 has 2 divisors, whose sum is σ = 3113504114. Its totient is φ = 3113504112.

The previous prime is 3113504101. The next prime is 3113504131. The reversal of 3113504113 is 3114053113.

3113504113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (3113504131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3063843904 + 49660209 = 55352^2 + 7047^2 .

It is a cyclic number.

It is not a de Polignac number, because 3113504113 - 2⁵ = 3113504081 is a prime.

It is not a weakly prime, because it can be changed into another prime (3113504813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556752056 + 1556752057.

It is an arithmetic number, because the mean of its divisors is an integer number (1556752057).

Almost surely, 2^3113504113 is an apocalyptic number.

It is an amenable number.

3113504113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3113504113 is an equidigital number, since it uses as much as digits as its factorization.

3113504113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

The square root of 3113504113 is about 55798.7823612666. The cubic root of 3113504113 is about 1460.2139101414.

Adding to 3113504113 its reverse (3114053113), we get a palindrome (6227557226).

The spelling of 3113504113 in words is "three billion, one hundred thirteen million, five hundred four thousand, one hundred thirteen".