Base | Representation |
---|---|
bin | 10010100011111… |
… | …001010000010001 |
3 | 210200221201201122 |
4 | 102203321100101 |
5 | 1114204240231 |
6 | 50522212025 |
7 | 10500565043 |
oct | 2243712021 |
9 | 720851648 |
10 | 311399441 |
11 | 14a860011 |
12 | 88354015 |
13 | 4c68c632 |
14 | 2d4dda93 |
15 | 1c51177b |
hex | 128f9411 |
311399441 has 2 divisors, whose sum is σ = 311399442. Its totient is φ = 311399440.
The previous prime is 311399401. The next prime is 311399479. The reversal of 311399441 is 144993113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 285745216 + 25654225 = 16904^2 + 5065^2 .
It is a cyclic number.
It is not a de Polignac number, because 311399441 - 26 = 311399377 is a prime.
It is a super-2 number, since 2×3113994412 = 193939223710224962, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (311399401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155699720 + 155699721.
It is an arithmetic number, because the mean of its divisors is an integer number (155699721).
Almost surely, 2311399441 is an apocalyptic number.
It is an amenable number.
311399441 is a deficient number, since it is larger than the sum of its proper divisors (1).
311399441 is an equidigital number, since it uses as much as digits as its factorization.
311399441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11664, while the sum is 35.
The square root of 311399441 is about 17646.5135650077. The cubic root of 311399441 is about 677.8068333260.
The spelling of 311399441 in words is "three hundred eleven million, three hundred ninety-nine thousand, four hundred forty-one".
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