3114013453 has 4 divisors (see below), whose sum is σ = 3120739648. Its totient is φ = 3107287260.

The previous prime is 3114013439. The next prime is 3114013477. The reversal of 3114013453 is 3543104113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3114013453 - 2⁵ = 3114013421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3114013753) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3362403 + ... + 3363328.

It is an arithmetic number, because the mean of its divisors is an integer number (780184912).

Almost surely, 2^3114013453 is an apocalyptic number.

It is an amenable number.

3114013453 is a deficient number, since it is larger than the sum of its proper divisors (6726195).

3114013453 is an equidigital number, since it uses as much as digits as its factorization.

3114013453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6726194.

The product of its (nonzero) digits is 2160, while the sum is 25.

The square root of 3114013453 is about 55803.3462527114. The cubic root of 3114013453 is about 1460.2935315554.

Adding to 3114013453 its reverse (3543104113), we get a palindrome (6657117566).

The spelling of 3114013453 in words is "three billion, one hundred fourteen million, thirteen thousand, four hundred fifty-three".