Search a number
-
+
31140142045 = 56228028409
BaseRepresentation
bin11101000000000110…
…001101101111011101
32222101012200010020021
4131000012031233131
51002233334021140
622150001152141
72151452561065
oct350006155735
988335603207
1031140142045
111222a886691
12605092b651
132c2365c16c
141715a363a5
15c23c8db4a
hex74018dbdd

31140142045 has 4 divisors (see below), whose sum is σ = 37368170460. Its totient is φ = 24912113632.

The previous prime is 31140142021. The next prime is 31140142051. The reversal of 31140142045 is 54024104113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 21090881529 + 10049260516 = 145227^2 + 100246^2 .

It is a cyclic number.

It is not a de Polignac number, because 31140142045 - 215 = 31140109277 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3114014200 + ... + 3114014209.

It is an arithmetic number, because the mean of its divisors is an integer number (9342042615).

Almost surely, 231140142045 is an apocalyptic number.

It is an amenable number.

31140142045 is a deficient number, since it is larger than the sum of its proper divisors (6228028415).

31140142045 is an equidigital number, since it uses as much as digits as its factorization.

31140142045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6228028414.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 31140142045 its reverse (54024104113), we get a palindrome (85164246158).

The spelling of 31140142045 in words is "thirty-one billion, one hundred forty million, one hundred forty-two thousand, forty-five".

Divisors: 1 5 6228028409 31140142045