Base | Representation |
---|---|
bin | 1110001010010011001011… |
… | …11001101010011111001111 |
3 | 11002020222100122111210111112 |
4 | 13011021211321222133033 |
5 | 13040200133430323210 |
6 | 150121342024442235 |
7 | 6362543512666640 |
oct | 705114571523717 |
9 | 132228318453445 |
10 | 31140222511055 |
11 | 9a16548868a19 |
12 | 35ab22561937b |
13 | 144b683406408 |
14 | 7992a27c36c7 |
15 | 390066a65d05 |
hex | 1c5265e6a7cf |
31140222511055 has 32 divisors (see below), whose sum is σ = 42905713858560. Its totient is φ = 21253782147840.
The previous prime is 31140222511009. The next prime is 31140222511081. The reversal of 31140222511055 is 55011522204113.
It is not a de Polignac number, because 31140222511055 - 210 = 31140222510031 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 30636395 + ... + 31636515.
It is an arithmetic number, because the mean of its divisors is an integer number (1340803558080).
Almost surely, 231140222511055 is an apocalyptic number.
31140222511055 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
31140222511055 is a deficient number, since it is larger than the sum of its proper divisors (11765491347505).
31140222511055 is a wasteful number, since it uses less digits than its factorization.
31140222511055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1004279.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 31140222511055 its reverse (55011522204113), we get a palindrome (86151744715168).
The spelling of 31140222511055 in words is "thirty-one trillion, one hundred forty billion, two hundred twenty-two million, five hundred eleven thousand, fifty-five".
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