Base | Representation |
---|---|
bin | 1110001010010100110110… |
… | …00110110100110000100001 |
3 | 11002021001122212011201122122 |
4 | 13011022123012310300201 |
5 | 13040204000434402231 |
6 | 150122010353114025 |
7 | 6362604602222606 |
oct | 705123306646041 |
9 | 132231585151578 |
10 | 31141115153441 |
11 | 9a169667253a7 |
12 | 35ab434558915 |
13 | 144b796324b87 |
14 | 7993491866ad |
15 | 3900ba0dc77b |
hex | 1c529b1b4c21 |
31141115153441 has 2 divisors, whose sum is σ = 31141115153442. Its totient is φ = 31141115153440.
The previous prime is 31141115153387. The next prime is 31141115153483. The reversal of 31141115153441 is 14435151114113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 25203120913441 + 5937994240000 = 5020271^2 + 2436800^2 .
It is a cyclic number.
It is not a de Polignac number, because 31141115153441 - 218 = 31141114891297 is a prime.
It is not a weakly prime, because it can be changed into another prime (31141115153641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15570557576720 + 15570557576721.
It is an arithmetic number, because the mean of its divisors is an integer number (15570557576721).
Almost surely, 231141115153441 is an apocalyptic number.
It is an amenable number.
31141115153441 is a deficient number, since it is larger than the sum of its proper divisors (1).
31141115153441 is an equidigital number, since it uses as much as digits as its factorization.
31141115153441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14400, while the sum is 35.
Adding to 31141115153441 its reverse (14435151114113), we get a palindrome (45576266267554).
The spelling of 31141115153441 in words is "thirty-one trillion, one hundred forty-one billion, one hundred fifteen million, one hundred fifty-three thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •