Base | Representation |
---|---|
bin | 100011011001111000101101… |
… | …1011110000101000111110011 |
3 | 1111211122120002120020110021102 |
4 | 1012303301123132011013303 |
5 | 311304310223431412243 |
6 | 3022200502034315015 |
7 | 122411266162026353 |
oct | 10663613336050763 |
9 | 1454576076213242 |
10 | 311421023310323 |
11 | 90256a06a24a63 |
12 | 2ab17592728a6b |
13 | 1049cb518510a4 |
14 | 56c8c02310b63 |
15 | 2600b974159b8 |
hex | 11b3c5b7851f3 |
311421023310323 has 2 divisors, whose sum is σ = 311421023310324. Its totient is φ = 311421023310322.
The previous prime is 311421023310311. The next prime is 311421023310377. The reversal of 311421023310323 is 323013320124113.
It is a weak prime.
It is an emirp because it is prime and its reverse (323013320124113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311421023310323 - 212 = 311421023306227 is a prime.
It is not a weakly prime, because it can be changed into another prime (311421023310923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155710511655161 + 155710511655162.
It is an arithmetic number, because the mean of its divisors is an integer number (155710511655162).
Almost surely, 2311421023310323 is an apocalyptic number.
311421023310323 is a deficient number, since it is larger than the sum of its proper divisors (1).
311421023310323 is an equidigital number, since it uses as much as digits as its factorization.
311421023310323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 311421023310323 its reverse (323013320124113), we get a palindrome (634434343434436).
The spelling of 311421023310323 in words is "three hundred eleven trillion, four hundred twenty-one billion, twenty-three million, three hundred ten thousand, three hundred twenty-three".
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