311424303424113 has 48 divisors (see below), whose sum is σ = 495663665664960. Its totient is φ = 188406754652160.

The previous prime is 311424303424099. The next prime is 311424303424123.

311424303424113 is a `hidden beast` number, since 3 + 1 + 142 + 430 + 3 + 42 + 41 + 1 + 3 = 666.

311424303424113 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 311424303424113 - 2⁶ = 311424303424049 is a prime.

It is not an unprimeable number, because it can be changed into a prime (311424303424123) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 16344208 + ... + 29832561.

It is an arithmetic number, because the mean of its divisors is an integer number (10326326368020).

Almost surely, 2^{311424303424113} is an apocalyptic number.

311424303424113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

It is an amenable number.

311424303424113 is a deficient number, since it is larger than the sum of its proper divisors (184239362240847).

311424303424113 is a wasteful number, since it uses less digits than its factorization.

311424303424113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46177371 (or 46177346 counting only the distinct ones).

The product of its (nonzero) digits is 82944, while the sum is 36.

It can be divided in two parts, 31142430 and 3424113, that added together give a palindrome (34566543).

The spelling of 311424303424113 in words is "three hundred eleven trillion, four hundred twenty-four billion, three hundred three million, four hundred twenty-four thousand, one hundred thirteen".