Base | Representation |
---|---|
bin | 100011011001111101000010… |
… | …0101001111010000010110001 |
3 | 1111211200110001100220001202000 |
4 | 1012303322010221322002301 |
5 | 311304433230334223441 |
6 | 3022205035012244213 |
7 | 122412045155262234 |
oct | 10663720451720261 |
9 | 1454613040801660 |
10 | 311430304211121 |
11 | 9025a939835107 |
12 | 2ab19342910669 |
13 | 104a09a0572a74 |
14 | 56c9442b6741b |
15 | 260103c0cc2b6 |
hex | 11b3e84a7a0b1 |
311430304211121 has 32 divisors (see below), whose sum is σ = 471477450055680. Its totient is φ = 203080853032848.
The previous prime is 311430304211023. The next prime is 311430304211123. The reversal of 311430304211121 is 121112403034113.
311430304211121 is a `hidden beast` number, since 3 + 1 + 1 + 430 + 3 + 0 + 4 + 211 + 12 + 1 = 666.
It is not a de Polignac number, because 311430304211121 - 29 = 311430304210609 is a prime.
It is a super-2 number, since 2×3114303042111212 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (311430304211123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 71494041 + ... + 75724886.
It is an arithmetic number, because the mean of its divisors is an integer number (14733670314240).
Almost surely, 2311430304211121 is an apocalyptic number.
It is an amenable number.
311430304211121 is a deficient number, since it is larger than the sum of its proper divisors (160047145844559).
311430304211121 is a wasteful number, since it uses less digits than its factorization.
311430304211121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147220650 (or 147220644 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 311430304211121 its reverse (121112403034113), we get a palindrome (432542707245234).
The spelling of 311430304211121 in words is "three hundred eleven trillion, four hundred thirty billion, three hundred four million, two hundred eleven thousand, one hundred twenty-one".
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