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311431006228873 is a prime number
BaseRepresentation
bin100011011001111101010111…
…0011111111001000110001001
31111211200111212021212021001111
41012303322232133321012021
5311304441200043310443
63022205232411050321
7122412101441316226
oct10663725637710611
91454614767767044
10311431006228873
119026016a032473
122ab194b9a409a1
13104a0a82b3a69b
1456c94ac0a894d
15260107da4c69d
hex11b3eae7f9189

311431006228873 has 2 divisors, whose sum is σ = 311431006228874. Its totient is φ = 311431006228872.

The previous prime is 311431006228861. The next prime is 311431006228879. The reversal of 311431006228873 is 378822600134113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 296472885318544 + 14958120910329 = 17218388^2 + 3867573^2 .

It is a cyclic number.

It is not a de Polignac number, because 311431006228873 - 29 = 311431006228361 is a prime.

It is not a weakly prime, because it can be changed into another prime (311431006228879) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715503114436 + 155715503114437.

It is an arithmetic number, because the mean of its divisors is an integer number (155715503114437).

Almost surely, 2311431006228873 is an apocalyptic number.

It is an amenable number.

311431006228873 is a deficient number, since it is larger than the sum of its proper divisors (1).

311431006228873 is an equidigital number, since it uses as much as digits as its factorization.

311431006228873 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1161216, while the sum is 49.

The spelling of 311431006228873 in words is "three hundred eleven trillion, four hundred thirty-one billion, six million, two hundred twenty-eight thousand, eight hundred seventy-three".