Base | Representation |
---|---|
bin | 1110001010011000100010… |
… | …11110011000111010010011 |
3 | 11002021020210020222100001201 |
4 | 13011030101132120322103 |
5 | 13040222032331323243 |
6 | 150122535413412031 |
7 | 6363005035053244 |
oct | 705142136307223 |
9 | 132236706870051 |
10 | 31143101042323 |
11 | 9a17795704086 |
12 | 35ab8a963a017 |
13 | 144ba2189b35a |
14 | 799496c0accb |
15 | 39018461404d |
hex | 1c5311798e93 |
31143101042323 has 2 divisors, whose sum is σ = 31143101042324. Its totient is φ = 31143101042322.
The previous prime is 31143101042303. The next prime is 31143101042359. The reversal of 31143101042323 is 32324010134113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31143101042323 - 213 = 31143101034131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31143101042291 and 31143101042300.
It is not a weakly prime, because it can be changed into another prime (31143101042303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571550521161 + 15571550521162.
It is an arithmetic number, because the mean of its divisors is an integer number (15571550521162).
Almost surely, 231143101042323 is an apocalyptic number.
31143101042323 is a deficient number, since it is larger than the sum of its proper divisors (1).
31143101042323 is an equidigital number, since it uses as much as digits as its factorization.
31143101042323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 31143101042323 its reverse (32324010134113), we get a palindrome (63467111176436).
The spelling of 31143101042323 in words is "thirty-one trillion, one hundred forty-three billion, one hundred one million, forty-two thousand, three hundred twenty-three".
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