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311431032012251 is a prime number
BaseRepresentation
bin100011011001111101011000…
…0000010001111110111011011
31111211200111221002101012012102
41012303322300002033313123
5311304441223143343001
63022205235131434015
7122412102203423354
oct10663726002176733
91454614832335172
10311431032012251
1190260182642948
122ab195065b590b
13104a0a88297318
1456c94b169ad2b
152601080e41e6b
hex11b3eb008fddb

311431032012251 has 2 divisors, whose sum is σ = 311431032012252. Its totient is φ = 311431032012250.

The previous prime is 311431032012241. The next prime is 311431032012293. The reversal of 311431032012251 is 152210230134113.

It is a weak prime.

It is an emirp because it is prime and its reverse (152210230134113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311431032012251 - 26 = 311431032012187 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (311431032012241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715516006125 + 155715516006126.

It is an arithmetic number, because the mean of its divisors is an integer number (155715516006126).

Almost surely, 2311431032012251 is an apocalyptic number.

311431032012251 is a deficient number, since it is larger than the sum of its proper divisors (1).

311431032012251 is an equidigital number, since it uses as much as digits as its factorization.

311431032012251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 311431032012251 its reverse (152210230134113), we get a palindrome (463641262146364).

The spelling of 311431032012251 in words is "three hundred eleven trillion, four hundred thirty-one billion, thirty-two million, twelve thousand, two hundred fifty-one".