Base | Representation |
---|---|
bin | 100011011001111101011000… |
… | …0000010001111110111011011 |
3 | 1111211200111221002101012012102 |
4 | 1012303322300002033313123 |
5 | 311304441223143343001 |
6 | 3022205235131434015 |
7 | 122412102203423354 |
oct | 10663726002176733 |
9 | 1454614832335172 |
10 | 311431032012251 |
11 | 90260182642948 |
12 | 2ab195065b590b |
13 | 104a0a88297318 |
14 | 56c94b169ad2b |
15 | 2601080e41e6b |
hex | 11b3eb008fddb |
311431032012251 has 2 divisors, whose sum is σ = 311431032012252. Its totient is φ = 311431032012250.
The previous prime is 311431032012241. The next prime is 311431032012293. The reversal of 311431032012251 is 152210230134113.
It is a weak prime.
It is an emirp because it is prime and its reverse (152210230134113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311431032012251 - 26 = 311431032012187 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (311431032012241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715516006125 + 155715516006126.
It is an arithmetic number, because the mean of its divisors is an integer number (155715516006126).
Almost surely, 2311431032012251 is an apocalyptic number.
311431032012251 is a deficient number, since it is larger than the sum of its proper divisors (1).
311431032012251 is an equidigital number, since it uses as much as digits as its factorization.
311431032012251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 311431032012251 its reverse (152210230134113), we get a palindrome (463641262146364).
The spelling of 311431032012251 in words is "three hundred eleven trillion, four hundred thirty-one billion, thirty-two million, twelve thousand, two hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •