Base | Representation |
---|---|
bin | 100011011001111101100000… |
… | …0101011110011110110011001 |
3 | 1111211200112122112222122221202 |
4 | 1012303323000223303312121 |
5 | 311304442311200434001 |
6 | 3022205322550443545 |
7 | 122412112134615623 |
oct | 10663730053636631 |
9 | 1454615575878852 |
10 | 311431311343001 |
11 | 9026030628a203 |
12 | 2ab195840635b5 |
13 | 104a0b011091a5 |
14 | 56c94da80dc13 |
15 | 260109a71b96b |
hex | 11b3ec0af3d99 |
311431311343001 has 2 divisors, whose sum is σ = 311431311343002. Its totient is φ = 311431311343000.
The previous prime is 311431311342971. The next prime is 311431311343069. The reversal of 311431311343001 is 100343113134113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 298216806792025 + 13214504550976 = 17268955^2 + 3635176^2 .
It is a cyclic number.
It is not a de Polignac number, because 311431311343001 - 230 = 311430237601177 is a prime.
It is not a weakly prime, because it can be changed into another prime (311431311343081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715655671500 + 155715655671501.
It is an arithmetic number, because the mean of its divisors is an integer number (155715655671501).
Almost surely, 2311431311343001 is an apocalyptic number.
It is an amenable number.
311431311343001 is a deficient number, since it is larger than the sum of its proper divisors (1).
311431311343001 is an equidigital number, since it uses as much as digits as its factorization.
311431311343001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 29.
Adding to 311431311343001 its reverse (100343113134113), we get a palindrome (411774424477114).
The spelling of 311431311343001 in words is "three hundred eleven trillion, four hundred thirty-one billion, three hundred eleven million, three hundred forty-three thousand, one".
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