31143140411 has 2 divisors, whose sum is σ = 31143140412. Its totient is φ = 31143140410.

The previous prime is 31143140387. The next prime is 31143140417. The reversal of 31143140411 is 11404134113.

It is a strong prime.

It is an emirp because it is prime and its reverse (11404134113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31143140411 - 2¹⁴ = 31143124027 is a prime.

It is a super-2 number, since 2×31143140411² (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (31143140417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571570205 + 15571570206.

It is an arithmetic number, because the mean of its divisors is an integer number (15571570206).

Almost surely, 2^31143140411 is an apocalyptic number.

31143140411 is a deficient number, since it is larger than the sum of its proper divisors (1).

31143140411 is an equidigital number, since it uses as much as digits as its factorization.

31143140411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 31143140411 its reverse (11404134113), we get a palindrome (42547274524).

The spelling of 31143140411 in words is "thirty-one billion, one hundred forty-three million, one hundred forty thousand, four hundred eleven".