Base | Representation |
---|---|
bin | 11101000000010010… |
… | …010110110101001001 |
3 | 2222101102122211102112 |
4 | 131000102112311021 |
5 | 1002240142400001 |
6 | 22150153312105 |
7 | 2151521615615 |
oct | 350022266511 |
9 | 88342584375 |
10 | 31143325001 |
11 | 12231660028 |
12 | 6051a05635 |
13 | 2c24204b79 |
14 | 1716224345 |
15 | c241bbcbb |
hex | 740496d49 |
31143325001 has 2 divisors, whose sum is σ = 31143325002. Its totient is φ = 31143325000.
The previous prime is 31143324991. The next prime is 31143325061. The reversal of 31143325001 is 10052334113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23451859600 + 7691465401 = 153140^2 + 87701^2 .
It is an emirp because it is prime and its reverse (10052334113) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31143325001 is a prime.
It is not a weakly prime, because it can be changed into another prime (31143325061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571662500 + 15571662501.
It is an arithmetic number, because the mean of its divisors is an integer number (15571662501).
Almost surely, 231143325001 is an apocalyptic number.
It is an amenable number.
31143325001 is a deficient number, since it is larger than the sum of its proper divisors (1).
31143325001 is an equidigital number, since it uses as much as digits as its factorization.
31143325001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 31143325001 its reverse (10052334113), we get a palindrome (41195659114).
The spelling of 31143325001 in words is "thirty-one billion, one hundred forty-three million, three hundred twenty-five thousand, one".
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