Base | Representation |
---|---|
bin | 1110001010011010001111… |
… | …11001000111110111000010 |
3 | 11002021100010212220102001000 |
4 | 13011031013321013313002 |
5 | 13040230420042120114 |
6 | 150123210145552430 |
7 | 6363036462202656 |
oct | 705150771076702 |
9 | 132240125812030 |
10 | 31144014020034 |
11 | 9a18113a9a813 |
12 | 35abb03345716 |
13 | 144bb38a89a56 |
14 | 799542184a66 |
15 | 3901d9855e09 |
hex | 1c5347e47dc2 |
31144014020034 has 64 divisors (see below), whose sum is σ = 69308175513600. Its totient is φ = 10366456890384.
The previous prime is 31144014020017. The next prime is 31144014020069. The reversal of 31144014020034 is 43002041044113.
31144014020034 is a `hidden beast` number, since 3 + 1 + 1 + 440 + 14 + 0 + 200 + 3 + 4 = 666.
It is a super-2 number, since 2×311440140200342 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 158875509 + ... + 159071415.
It is an arithmetic number, because the mean of its divisors is an integer number (1082940242400).
Almost surely, 231144014020034 is an apocalyptic number.
31144014020034 is an abundant number, since it is smaller than the sum of its proper divisors (38164161493566).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31144014020034 is a wasteful number, since it uses less digits than its factorization.
31144014020034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 200124 (or 200118 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 31144014020034 its reverse (43002041044113), we get a palindrome (74146055064147).
The spelling of 31144014020034 in words is "thirty-one trillion, one hundred forty-four billion, fourteen million, twenty thousand, thirty-four".
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