Base | Representation |
---|---|
bin | 1110001010011010010000… |
… | …10100101000100111100111 |
3 | 11002021100011101110211010200 |
4 | 13011031020110220213213 |
5 | 13040230423413411403 |
6 | 150123211004321543 |
7 | 6363036610411263 |
oct | 705151024504747 |
9 | 132240141424120 |
10 | 31144021232103 |
11 | 9a181180762aa |
12 | 35abb058432b3 |
13 | 144bb3a413650 |
14 | 7995431010a3 |
15 | 3901da2ccca3 |
hex | 1c53485289e7 |
31144021232103 has 48 divisors (see below), whose sum is σ = 48633884242944. Its totient is φ = 19091334968640.
The previous prime is 31144021232087. The next prime is 31144021232287. The reversal of 31144021232103 is 30123212044113.
31144021232103 is a `hidden beast` number, since 3 + 1 + 1 + 440 + 2 + 1 + 2 + 3 + 210 + 3 = 666.
It is not a de Polignac number, because 31144021232103 - 24 = 31144021232087 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31144021232003) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 603178098 + ... + 603229728.
It is an arithmetic number, because the mean of its divisors is an integer number (1013205921728).
Almost surely, 231144021232103 is an apocalyptic number.
31144021232103 is a deficient number, since it is larger than the sum of its proper divisors (17489863010841).
31144021232103 is a wasteful number, since it uses less digits than its factorization.
31144021232103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71516 (or 71513 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 31144021232103 its reverse (30123212044113), we get a palindrome (61267233276216).
The spelling of 31144021232103 in words is "thirty-one trillion, one hundred forty-four billion, twenty-one million, two hundred thirty-two thousand, one hundred three".
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