Base | Representation |
---|---|
bin | 100011011010000001101100… |
… | …0101101010000101100111011 |
3 | 1111211201101212021211210000021 |
4 | 1012310003120231100230323 |
5 | 311310114220400423344 |
6 | 3022213411201151311 |
7 | 122412551033601535 |
oct | 10664033055205473 |
9 | 1454641767753007 |
10 | 311440304311099 |
11 | 90264100608247 |
12 | 2ab1b27392b537 |
13 | 104a19052968a2 |
14 | 56c9b10d14855 |
15 | 2601424ea9b84 |
hex | 11b40d8b50b3b |
311440304311099 has 2 divisors, whose sum is σ = 311440304311100. Its totient is φ = 311440304311098.
The previous prime is 311440304311061. The next prime is 311440304311141. The reversal of 311440304311099 is 990113403044113.
It is a weak prime.
It is an emirp because it is prime and its reverse (990113403044113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311440304311099 - 29 = 311440304310587 is a prime.
It is not a weakly prime, because it can be changed into another prime (311440304311039) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155720152155549 + 155720152155550.
It is an arithmetic number, because the mean of its divisors is an integer number (155720152155550).
Almost surely, 2311440304311099 is an apocalyptic number.
311440304311099 is a deficient number, since it is larger than the sum of its proper divisors (1).
311440304311099 is an equidigital number, since it uses as much as digits as its factorization.
311440304311099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 43.
The spelling of 311440304311099 in words is "three hundred eleven trillion, four hundred forty billion, three hundred four million, three hundred eleven thousand, ninety-nine".
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