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311442132134443 is a prime number
BaseRepresentation
bin100011011010000010100010…
…1101001110110101000101011
31111211201120120200012211021011
41012310011011221312220223
5311310131441311300233
63022214312413524351
7122412644240050552
oct10664050551665053
91454646520184234
10311442132134443
1190264959345a52
122ab1b6a3aa36b7
13104a1b36b78c6b
1456c9c45990d99
1526014d06ac0cd
hex11b4145a76a2b

311442132134443 has 2 divisors, whose sum is σ = 311442132134444. Its totient is φ = 311442132134442.

The previous prime is 311442132134417. The next prime is 311442132134447. The reversal of 311442132134443 is 344431231244113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 311442132134443 - 229 = 311441595263531 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311442132134396 and 311442132134405.

It is not a weakly prime, because it can be changed into another prime (311442132134447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155721066067221 + 155721066067222.

It is an arithmetic number, because the mean of its divisors is an integer number (155721066067222).

Almost surely, 2311442132134443 is an apocalyptic number.

311442132134443 is a deficient number, since it is larger than the sum of its proper divisors (1).

311442132134443 is an equidigital number, since it uses as much as digits as its factorization.

311442132134443 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 331776, while the sum is 40.

Adding to 311442132134443 its reverse (344431231244113), we get a palindrome (655873363378556).

The spelling of 311442132134443 in words is "three hundred eleven trillion, four hundred forty-two billion, one hundred thirty-two million, one hundred thirty-four thousand, four hundred forty-three".