Base | Representation |
---|---|
bin | 101101010101101000111… |
… | …101010101111000110001 |
3 | 102000211221101000120120212 |
4 | 231111220331111320301 |
5 | 402021233210403442 |
6 | 10343143102113505 |
7 | 441044526514106 |
oct | 55255075257061 |
9 | 12024841016525 |
10 | 3115612200497 |
11 | aa1361955115 |
12 | 4239b027b895 |
13 | 197a549665b4 |
14 | aab215bcaad |
15 | 5609e3c0a82 |
hex | 2d568f55e31 |
3115612200497 has 2 divisors, whose sum is σ = 3115612200498. Its totient is φ = 3115612200496.
The previous prime is 3115612200451. The next prime is 3115612200511. The reversal of 3115612200497 is 7940022165113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1907600183281 + 1208012017216 = 1381159^2 + 1099096^2 .
It is a cyclic number.
It is not a de Polignac number, because 3115612200497 - 26 = 3115612200433 is a prime.
It is not a weakly prime, because it can be changed into another prime (3115612200097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557806100248 + 1557806100249.
It is an arithmetic number, because the mean of its divisors is an integer number (1557806100249).
Almost surely, 23115612200497 is an apocalyptic number.
It is an amenable number.
3115612200497 is a deficient number, since it is larger than the sum of its proper divisors (1).
3115612200497 is an equidigital number, since it uses as much as digits as its factorization.
3115612200497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90720, while the sum is 41.
The spelling of 3115612200497 in words is "three trillion, one hundred fifteen billion, six hundred twelve million, two hundred thousand, four hundred ninety-seven".
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