Base | Representation |
---|---|
bin | 101101010110101011001… |
… | …101100010011010100111 |
3 | 102000221210211120202101120 |
4 | 231112223031202122213 |
5 | 402031022234224000 |
6 | 10343445250225023 |
7 | 441114214461015 |
oct | 55265315423247 |
9 | 12027724522346 |
10 | 3116723742375 |
11 | aa1882332a71 |
12 | 424060585173 |
13 | 197ba1028899 |
14 | aabc90838b5 |
15 | 56116c866a0 |
hex | 2d5ab3626a7 |
3116723742375 has 16 divisors (see below), whose sum is σ = 5186228307936. Its totient is φ = 1662252662400.
The previous prime is 3116723742361. The next prime is 3116723742389. The reversal of 3116723742375 is 5732473276113.
3116723742375 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (3116723742361) and next prime (3116723742389).
It is not a de Polignac number, because 3116723742375 - 25 = 3116723742343 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4155631282 + ... + 4155632031.
It is an arithmetic number, because the mean of its divisors is an integer number (324139269246).
Almost surely, 23116723742375 is an apocalyptic number.
3116723742375 is a deficient number, since it is larger than the sum of its proper divisors (2069504565561).
3116723742375 is an equidigital number, since it uses as much as digits as its factorization.
3116723742375 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8311263331 (or 8311263321 counting only the distinct ones).
The product of its digits is 4445280, while the sum is 51.
The spelling of 3116723742375 in words is "three trillion, one hundred sixteen billion, seven hundred twenty-three million, seven hundred forty-two thousand, three hundred seventy-five".
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