Search a number
-
+
311814354613 = 793947017147
BaseRepresentation
bin1001000100110011001…
…01010111011010110101
31002210211212201102111111
410202121211113122311
520102043433321423
6355125011435021
731346023166026
oct4423145273265
91083755642444
10311814354613
1111027008a833
1250521bb5a71
1323533693a98
1411140236c4d
15819e9ad60d
hex48999576b5

311814354613 has 4 divisors (see below), whose sum is σ = 315761371840. Its totient is φ = 307867337388.

The previous prime is 311814354589. The next prime is 311814354623. The reversal of 311814354613 is 316453418113.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 316453418113 = 745207631159.

It is a cyclic number.

It is not a de Polignac number, because 311814354613 - 217 = 311814223541 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311814354623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1973508495 + ... + 1973508652.

It is an arithmetic number, because the mean of its divisors is an integer number (78940342960).

Almost surely, 2311814354613 is an apocalyptic number.

It is an amenable number.

311814354613 is a deficient number, since it is larger than the sum of its proper divisors (3947017227).

311814354613 is an equidigital number, since it uses as much as digits as its factorization.

311814354613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3947017226.

The product of its digits is 103680, while the sum is 40.

The spelling of 311814354613 in words is "three hundred eleven billion, eight hundred fourteen million, three hundred fifty-four thousand, six hundred thirteen".

Divisors: 1 79 3947017147 311814354613