Base | Representation |
---|---|
bin | 1001000101000011111… |
… | …10011101000100100001 |
3 | 1002211012200122112012201 |
4 | 10202201332131010201 |
5 | 20102341004232324 |
6 | 355151001253201 |
7 | 31352353005403 |
oct | 4424176350441 |
9 | 1084180575181 |
10 | 311955149089 |
11 | 110332604801 |
12 | 50561194201 |
13 | 235568bb91c |
14 | 11154c06b73 |
15 | 81ac020444 |
hex | 48a1f9d121 |
311955149089 has 2 divisors, whose sum is σ = 311955149090. Its totient is φ = 311955149088.
The previous prime is 311955149069. The next prime is 311955149101. The reversal of 311955149089 is 980941559113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 282563475489 + 29391673600 = 531567^2 + 171440^2 .
It is a cyclic number.
It is not a de Polignac number, because 311955149089 - 211 = 311955147041 is a prime.
It is not a weakly prime, because it can be changed into another prime (311955149039) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155977574544 + 155977574545.
It is an arithmetic number, because the mean of its divisors is an integer number (155977574545).
Almost surely, 2311955149089 is an apocalyptic number.
It is an amenable number.
311955149089 is a deficient number, since it is larger than the sum of its proper divisors (1).
311955149089 is an equidigital number, since it uses as much as digits as its factorization.
311955149089 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1749600, while the sum is 55.
The spelling of 311955149089 in words is "three hundred eleven billion, nine hundred fifty-five million, one hundred forty-nine thousand, eighty-nine".
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