312000440124433 has 2 divisors, whose sum is σ = 312000440124434. Its totient is φ = 312000440124432.

The previous prime is 312000440124407. The next prime is 312000440124521. The reversal of 312000440124433 is 334421044000213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 194690897236224 + 117309542888209 = 13953168^2 + 10830953^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-312000440124433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 312000440124395 and 312000440124404.

It is not a weakly prime, because it can be changed into another prime (312000440127433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156000220062216 + 156000220062217.

It is an arithmetic number, because the mean of its divisors is an integer number (156000220062217).

Almost surely, 2^{312000440124433} is an apocalyptic number.

It is an amenable number.

312000440124433 is a deficient number, since it is larger than the sum of its proper divisors (1).

312000440124433 is an equidigital number, since it uses as much as digits as its factorization.

312000440124433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 312000440124433 its reverse (334421044000213), we get a palindrome (646421484124646).

The spelling of 312000440124433 in words is "three hundred twelve trillion, four hundred forty million, one hundred twenty-four thousand, four hundred thirty-three".