Base | Representation |
---|---|
bin | 100011011110000110110110… |
… | …1001001001100111011100100 |
3 | 1111220201000110220220121222221 |
4 | 1012330031231021030323210 |
5 | 311343311313421142012 |
6 | 3023323202321202124 |
7 | 122501224054031233 |
oct | 10674155511147344 |
9 | 1456630426817887 |
10 | 312001140412132 |
11 | 9045aa38a00896 |
12 | 2ababab2790344 |
13 | 10512773154682 |
14 | 5708d15a72b1a |
15 | 2610ceb949507 |
hex | 11bc36d24cee4 |
312001140412132 has 12 divisors (see below), whose sum is σ = 546385693549696. Its totient is φ = 155890942255080.
The previous prime is 312001140412081. The next prime is 312001140412133. The reversal of 312001140412132 is 231214041100213.
It is a junction number, because it is equal to n+sod(n) for n = 312001140412097 and 312001140412106.
It is not an unprimeable number, because it can be changed into a prime (312001140412133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27406981344 + ... + 27406992727.
Almost surely, 2312001140412132 is an apocalyptic number.
It is an amenable number.
312001140412132 is a deficient number, since it is larger than the sum of its proper divisors (234384553137564).
312001140412132 is a wasteful number, since it uses less digits than its factorization.
312001140412132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54813975498 (or 54813975496 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 312001140412132 its reverse (231214041100213), we get a palindrome (543215181512345).
The spelling of 312001140412132 in words is "three hundred twelve trillion, one billion, one hundred forty million, four hundred twelve thousand, one hundred thirty-two".
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