Base | Representation |
---|---|
bin | 100011011110000110110110… |
… | …1001100001111101110111011 |
3 | 1111220201000110222102011112012 |
4 | 1012330031231030033232323 |
5 | 311343311314122210133 |
6 | 3023323202350240135 |
7 | 122501224063563425 |
oct | 10674155514175673 |
9 | 1456630428364465 |
10 | 312001141210043 |
11 | 9045aa393a631a |
12 | 2ababab2ab604b |
13 | 105127733738cc |
14 | 5708d15bdd815 |
15 | 2610ceba55b48 |
hex | 11bc36d30fbbb |
312001141210043 has 2 divisors, whose sum is σ = 312001141210044. Its totient is φ = 312001141210042.
The previous prime is 312001141210037. The next prime is 312001141210063. The reversal of 312001141210043 is 340012141100213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312001141210043 - 24 = 312001141210027 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (312001141210063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156000570605021 + 156000570605022.
It is an arithmetic number, because the mean of its divisors is an integer number (156000570605022).
Almost surely, 2312001141210043 is an apocalyptic number.
312001141210043 is a deficient number, since it is larger than the sum of its proper divisors (1).
312001141210043 is an equidigital number, since it uses as much as digits as its factorization.
312001141210043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 312001141210043 its reverse (340012141100213), we get a palindrome (652013282310256).
The spelling of 312001141210043 in words is "three hundred twelve trillion, one billion, one hundred forty-one million, two hundred ten thousand, forty-three".
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