31200134113 has 2 divisors, whose sum is σ = 31200134114. Its totient is φ = 31200134112.

The previous prime is 31200134071. The next prime is 31200134197. The reversal of 31200134113 is 31143100213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26924543569 + 4275590544 = 164087^2 + 65388^2 .

It is an emirp because it is prime and its reverse (31143100213) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31200134113 is a prime.

It is not a weakly prime, because it can be changed into another prime (31200134513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15600067056 + 15600067057.

It is an arithmetic number, because the mean of its divisors is an integer number (15600067057).

Almost surely, 2^31200134113 is an apocalyptic number.

It is an amenable number.

31200134113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31200134113 is an equidigital number, since it uses as much as digits as its factorization.

31200134113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 31200134113 its reverse (31143100213), we get a palindrome (62343234326).

The spelling of 31200134113 in words is "thirty-one billion, two hundred million, one hundred thirty-four thousand, one hundred thirteen".