Base | Representation |
---|---|
bin | 101101011001101111110… |
… | …000000010100010110001 |
3 | 102001021022122011221210021 |
4 | 231121233300002202301 |
5 | 402104300401334301 |
6 | 10345152400403441 |
7 | 441262013645245 |
oct | 55315760024261 |
9 | 12037278157707 |
10 | 3120021121201 |
11 | aa3214647536 |
12 | 424820916581 |
13 | 1982a8200b0a |
14 | ab01cd7a425 |
15 | 5625b4bc8a1 |
hex | 2d66fc028b1 |
3120021121201 has 2 divisors, whose sum is σ = 3120021121202. Its totient is φ = 3120021121200.
The previous prime is 3120021121159. The next prime is 3120021121223. The reversal of 3120021121201 is 1021211200213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1663522130176 + 1456498991025 = 1289776^2 + 1206855^2 .
It is a cyclic number.
It is not a de Polignac number, because 3120021121201 - 211 = 3120021119153 is a prime.
It is not a weakly prime, because it can be changed into another prime (3120021121241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560010560600 + 1560010560601.
It is an arithmetic number, because the mean of its divisors is an integer number (1560010560601).
Almost surely, 23120021121201 is an apocalyptic number.
It is an amenable number.
3120021121201 is a deficient number, since it is larger than the sum of its proper divisors (1).
3120021121201 is an equidigital number, since it uses as much as digits as its factorization.
3120021121201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 3120021121201 its reverse (1021211200213), we get a palindrome (4141232321414).
The spelling of 3120021121201 in words is "three trillion, one hundred twenty billion, twenty-one million, one hundred twenty-one thousand, two hundred one".
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