Base | Representation |
---|---|
bin | 1110001100000011000101… |
… | …11011001010010011011011 |
3 | 11002110201102200212211222101 |
4 | 13012001202323022103123 |
5 | 13042141204320122021 |
6 | 150205115415104231 |
7 | 6400101400125142 |
oct | 706014273122333 |
9 | 132421380784871 |
10 | 31200302114011 |
11 | 9a39a79175948 |
12 | 35ba9b2072077 |
13 | 14542394b5034 |
14 | 79c161a78759 |
15 | 3918d128ea91 |
hex | 1c6062eca4db |
31200302114011 has 2 divisors, whose sum is σ = 31200302114012. Its totient is φ = 31200302114010.
The previous prime is 31200302113943. The next prime is 31200302114021. The reversal of 31200302114011 is 11041120300213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31200302114011 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31200302114011.
It is not a weakly prime, because it can be changed into another prime (31200302114021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15600151057005 + 15600151057006.
It is an arithmetic number, because the mean of its divisors is an integer number (15600151057006).
Almost surely, 231200302114011 is an apocalyptic number.
31200302114011 is a deficient number, since it is larger than the sum of its proper divisors (1).
31200302114011 is an equidigital number, since it uses as much as digits as its factorization.
31200302114011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 31200302114011 its reverse (11041120300213), we get a palindrome (42241422414224).
The spelling of 31200302114011 in words is "thirty-one trillion, two hundred billion, three hundred two million, one hundred fourteen thousand, eleven".
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