Search a number
-
+
312011114 = 2156005557
BaseRepresentation
bin10010100110001…
…110100101101010
3210202002210210012
4102212032211222
51114333323424
650543251522
710506023252
oct2246164552
9722083705
10312011114
11150138628
12885a9ba2
134c844b7c
142d61c962
151c5d2b0e
hex1298e96a

312011114 has 4 divisors (see below), whose sum is σ = 468016674. Its totient is φ = 156005556.

The previous prime is 312011111. The next prime is 312011137. The reversal of 312011114 is 411110213.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 411110213 = 1367300739.

It can be written as a sum of positive squares in only one way, i.e., 309232225 + 2778889 = 17585^2 + 1667^2 .

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (312011111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78002777 + ... + 78002780.

Almost surely, 2312011114 is an apocalyptic number.

312011114 is a deficient number, since it is larger than the sum of its proper divisors (156005560).

312011114 is a wasteful number, since it uses less digits than its factorization.

312011114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156005559.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 312011114 is about 17663.8363330280. The cubic root of 312011114 is about 678.2503419098.

Adding to 312011114 its reverse (411110213), we get a palindrome (723121327).

Subtracting 312011114 from its reverse (411110213), we obtain a palindrome (99099099).

The spelling of 312011114 in words is "three hundred twelve million, eleven thousand, one hundred fourteen".

Divisors: 1 2 156005557 312011114