Base | Representation |
---|---|
bin | 100011011110001011100010… |
… | …0101111100001110010001010 |
3 | 1111220201222102222211012221200 |
4 | 1012330113010233201302022 |
5 | 311343442414200331102 |
6 | 3023331544433245030 |
7 | 122502031254151053 |
oct | 10674270457416212 |
9 | 1456658388735850 |
10 | 312011200011402 |
11 | 904642303226a1 |
12 | 2abb1a3b703776 |
13 | 105136b72ab588 |
14 | 57095cbaab72a |
15 | 26111d9b7b51c |
hex | 11bc5c4be1c8a |
312011200011402 has 48 divisors (see below), whose sum is σ = 678217695442560. Its totient is φ = 103666302208800.
The previous prime is 312011200011377. The next prime is 312011200011443. The reversal of 312011200011402 is 204110002110213.
312011200011402 is a `hidden beast` number, since 31 + 20 + 1 + 1 + 200 + 0 + 11 + 402 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 196027452 + ... + 197612712.
It is an arithmetic number, because the mean of its divisors is an integer number (14129535321720).
Almost surely, 2312011200011402 is an apocalyptic number.
312011200011402 is an abundant number, since it is smaller than the sum of its proper divisors (366206495431158).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312011200011402 is a wasteful number, since it uses less digits than its factorization.
312011200011402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1620739 (or 1620736 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 312011200011402 its reverse (204110002110213), we get a palindrome (516121202121615).
The spelling of 312011200011402 in words is "three hundred twelve trillion, eleven billion, two hundred million, eleven thousand, four hundred two".
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