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31201222100103 = 3211739754756509
BaseRepresentation
bin1110001100000100110011…
…10000101000010010000111
311002110210210210222222122100
413012002121300220102013
513042200100324200403
6150205351001403143
76400133240644266
oct706023160502207
9132423723888570
1031201222100103
119a3a400509030
1235bb00a1994b3
131454354c886c3
1479c20bd185dd
15391936e182a3
hex1c6099c28487

31201222100103 has 48 divisors (see below), whose sum is σ = 49239486691200. Its totient is φ = 18881406815040.

The previous prime is 31201222100089. The next prime is 31201222100117. The reversal of 31201222100103 is 30100122210213.

It is an interprime number because it is at equal distance from previous prime (31201222100089) and next prime (31201222100117).

It is not a de Polignac number, because 31201222100103 - 25 = 31201222100071 is a prime.

It is a super-3 number, since 3×312012221001033 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31201222100143) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 552117813 + ... + 552174321.

It is an arithmetic number, because the mean of its divisors is an integer number (1025822639400).

Almost surely, 231201222100103 is an apocalyptic number.

31201222100103 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

31201222100103 is a deficient number, since it is larger than the sum of its proper divisors (18038264591097).

31201222100103 is a wasteful number, since it uses less digits than its factorization.

31201222100103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64812 (or 64809 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 31201222100103 its reverse (30100122210213), we get a palindrome (61301344310316).

It can be divided in two parts, 3120122 and 2100103, that added together give a palindrome (5220225).

The spelling of 31201222100103 in words is "thirty-one trillion, two hundred one billion, two hundred twenty-two million, one hundred thousand, one hundred three".

Divisors: 1 3 9 11 33 99 739 2217 6651 7547 8129 22641 24387 56509 67923 73161 83017 169527 249051 508581 621599 747153 1864797 5577233 5594391 16731699 41760151 50195097 61349563 125280453 184048689 375841359 426473423 459361661 552146067 1279420269 1378084983 3838260807 4134254949 4691207653 14073622959 42220868877 315163859597 945491578791 2836474736373 3466802455567 10400407366701 31201222100103