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312013113000331 is a prime number
BaseRepresentation
bin100011011110001100011011…
…0110001000000000110001011
31111220202011101022110010102111
41012330120312301000012023
5311344010323412002311
63023332502331243151
7122502126543246211
oct10674306661000613
91456664338403374
10312013113000331
119046502213a586
122abb22942a94b7
131051393070c2a2
14570972db96cb1
15261129caa2d21
hex11bc636c4018b

312013113000331 has 2 divisors, whose sum is σ = 312013113000332. Its totient is φ = 312013113000330.

The previous prime is 312013113000263. The next prime is 312013113000409. The reversal of 312013113000331 is 133000311310213.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 312013113000331 - 241 = 309814089744779 is a prime.

It is a super-2 number, since 2×3120131130003312 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (312013113000431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156006556500165 + 156006556500166.

It is an arithmetic number, because the mean of its divisors is an integer number (156006556500166).

Almost surely, 2312013113000331 is an apocalyptic number.

312013113000331 is a deficient number, since it is larger than the sum of its proper divisors (1).

312013113000331 is an equidigital number, since it uses as much as digits as its factorization.

312013113000331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 312013113000331 its reverse (133000311310213), we get a palindrome (445013424310544).

The spelling of 312013113000331 in words is "three hundred twelve trillion, thirteen billion, one hundred thirteen million, three hundred thirty-one", and thus it is an aban number.