Base | Representation |
---|---|
bin | 100011011110001100011011… |
… | …0110001000000000110001011 |
3 | 1111220202011101022110010102111 |
4 | 1012330120312301000012023 |
5 | 311344010323412002311 |
6 | 3023332502331243151 |
7 | 122502126543246211 |
oct | 10674306661000613 |
9 | 1456664338403374 |
10 | 312013113000331 |
11 | 9046502213a586 |
12 | 2abb22942a94b7 |
13 | 1051393070c2a2 |
14 | 570972db96cb1 |
15 | 261129caa2d21 |
hex | 11bc636c4018b |
312013113000331 has 2 divisors, whose sum is σ = 312013113000332. Its totient is φ = 312013113000330.
The previous prime is 312013113000263. The next prime is 312013113000409. The reversal of 312013113000331 is 133000311310213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312013113000331 - 241 = 309814089744779 is a prime.
It is a super-2 number, since 2×3120131130003312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (312013113000431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156006556500165 + 156006556500166.
It is an arithmetic number, because the mean of its divisors is an integer number (156006556500166).
Almost surely, 2312013113000331 is an apocalyptic number.
312013113000331 is a deficient number, since it is larger than the sum of its proper divisors (1).
312013113000331 is an equidigital number, since it uses as much as digits as its factorization.
312013113000331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 312013113000331 its reverse (133000311310213), we get a palindrome (445013424310544).
The spelling of 312013113000331 in words is "three hundred twelve trillion, thirteen billion, one hundred thirteen million, three hundred thirty-one", and thus it is an aban number.
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