Search a number
-
+
3120132014 = 210333150979
BaseRepresentation
bin1011100111111001…
…0110111110101110
322001110002010110222
42321332112332232
522342223211024
61233335131342
7140214453536
oct27176267656
98043063428
103120132014
1113612623aa
12730b13b52
133a955657c
142185584c6
15133dc385e
hexb9f96fae

3120132014 has 8 divisors (see below), whose sum is σ = 4680681960. Its totient is φ = 1559904696.

The previous prime is 3120131983. The next prime is 3120132017. The reversal of 3120132014 is 4102310213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×31201320143 (a number of 29 digits) contains 333 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3120131983 and 3120132001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3120132017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54824 + ... + 96155.

It is an arithmetic number, because the mean of its divisors is an integer number (585085245).

Almost surely, 23120132014 is an apocalyptic number.

3120132014 is a deficient number, since it is larger than the sum of its proper divisors (1560549946).

3120132014 is a wasteful number, since it uses less digits than its factorization.

3120132014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161314.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 3120132014 is about 55858.1418774381. The cubic root of 3120132014 is about 1461.2493237791.

Adding to 3120132014 its reverse (4102310213), we get a palindrome (7222442227).

The spelling of 3120132014 in words is "three billion, one hundred twenty million, one hundred thirty-two thousand, fourteen".

Divisors: 1 2 10333 20666 150979 301958 1560066007 3120132014