Base | Representation |
---|---|
bin | 101101011001111010011… |
… | …110001110110100111101 |
3 | 102001021210011122212021020 |
4 | 231121322132032310331 |
5 | 402110132424033201 |
6 | 10345222304054353 |
7 | 441266326630035 |
oct | 55317236166475 |
9 | 12037704585236 |
10 | 3120201002301 |
11 | aa32a71388a9 |
12 | 4248710043b9 |
13 | 198306562836 |
14 | ab038c028c5 |
15 | 5626c1a0a36 |
hex | 2d67a78ed3d |
3120201002301 has 16 divisors (see below), whose sum is σ = 4310904744960. Its totient is φ = 2006040319920.
The previous prime is 3120201002291. The next prime is 3120201002341. The reversal of 3120201002301 is 1032001020213.
3120201002301 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3120201002301 - 215 = 3120200969533 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3120201002341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 153075915 + ... + 153096296.
It is an arithmetic number, because the mean of its divisors is an integer number (269431546560).
Almost surely, 23120201002301 is an apocalyptic number.
It is an amenable number.
3120201002301 is a deficient number, since it is larger than the sum of its proper divisors (1190703742659).
3120201002301 is a wasteful number, since it uses less digits than its factorization.
3120201002301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 306172336.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 3120201002301 its reverse (1032001020213), we get a palindrome (4152202022514).
The spelling of 3120201002301 in words is "three trillion, one hundred twenty billion, two hundred one million, two thousand, three hundred one".
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