Base | Representation |
---|---|
bin | 1001000101001011110… |
… | …10000111101001011011 |
3 | 1002211101021210021112001 |
4 | 10202211322013221123 |
5 | 20103004401343002 |
6 | 355201315301431 |
7 | 31354113526225 |
oct | 4424572075133 |
9 | 1084337707461 |
10 | 312021121627 |
11 | 110366874966 |
12 | 5057b2aa877 |
13 | 2356747a227 |
14 | 1115d89b415 |
15 | 81b2c02a87 |
hex | 48a5e87a5b |
312021121627 has 2 divisors, whose sum is σ = 312021121628. Its totient is φ = 312021121626.
The previous prime is 312021121553. The next prime is 312021121637. The reversal of 312021121627 is 726121120213.
It is a strong prime.
It is an emirp because it is prime and its reverse (726121120213) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312021121627 is a prime.
It is a super-2 number, since 2×3120211216272 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 312021121595 and 312021121604.
It is not a weakly prime, because it can be changed into another prime (312021121637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156010560813 + 156010560814.
It is an arithmetic number, because the mean of its divisors is an integer number (156010560814).
Almost surely, 2312021121627 is an apocalyptic number.
312021121627 is a deficient number, since it is larger than the sum of its proper divisors (1).
312021121627 is an equidigital number, since it uses as much as digits as its factorization.
312021121627 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 28.
The spelling of 312021121627 in words is "three hundred twelve billion, twenty-one million, one hundred twenty-one thousand, six hundred twenty-seven".
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